document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=840582>Question 840582</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangular swimming pool is 24 meters less than the length, and the perimeter is 108 meters. Find its dimensions. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #506298 by </B><A HREF=/tutors/aboutme.mpl?userid=thejackal><B>thejackal(72)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=thejackal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=thejackal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=506298\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P = perimeter = 108; P is found by the equation P = 2w + 2l, where w is width and l is length\r<BR>\n" );
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document.write( "since w = l - 24\r<BR>\n" );
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document.write( "then P = 2w + 2l can be written as P = 2(l-24) + 2l\r<BR>\n" );
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document.write( "thus 108 = 2l - 48 + 2l\r<BR>\n" );
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document.write( "108 + 48 = 4l\r<BR>\n" );
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document.write( "156/4 = l = length = 39\r<BR>\n" );
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document.write( "i'll leave you to work out the width<BR>\n" );
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