document.write( "Question 70880: 1)3x² + 5x – 12 = 0
\n" ); document.write( "2)2x² + 2x – 1 = 0 \n" ); document.write( "
Algebra.Com's Answer #50627 by checkley75(3666)\"\" \"About 
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3X^2+5X-12=0
\n" ); document.write( "(3X-4)(X+3)=0
\n" ); document.write( "3X-4=0
\n" ); document.write( "3X=4
\n" ); document.write( "X=3/4 ANSWER.
\n" ); document.write( "X+3=0
\n" ); document.write( "X=-3 ANSWER.
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\n" ); document.write( "2X^2+2X-1=0
\n" ); document.write( "USING THE QUADRATIC EQUATION WE GET
\n" ); document.write( "X=(-B+-SQRT[B^2-4*A*C])/2A
\n" ); document.write( "X=(-2+-SQRT[4-4*2*-1])/2*2
\n" ); document.write( "X=(-2+-SQRT[4+8])/4
\n" ); document.write( "X=(-2+-SQRT12)/4
\n" ); document.write( "X=(-2+-3.464)/4
\n" ); document.write( "X=(-2+3.464)/4
\n" ); document.write( "X=1.464/4
\n" ); document.write( "X=.366 ANSWER
\n" ); document.write( "X=(-2-3.464)/4
\n" ); document.write( "X=-5.464/4
\n" ); document.write( "X=-1.366 ANSWER
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