document.write( "Question 840551: How many ways are there to choose a committee of 7 people from a group of 10 people? \n" ); document.write( "
Algebra.Com's Answer #506268 by thejackal(72)\"\" \"About 
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lets write it differently shall we.\r
\n" ); document.write( "\n" ); document.write( "there are 10 committee members, so lets number them as committee member numbers 1,2,3,4,5,6,7,8,9,10\r
\n" ); document.write( "\n" ); document.write( "we want seven. First of all there are a few very important things to note about the question.
\n" ); document.write( "1. Order is not important. I need to choose 7 members, not 7 consecutive members but any 7 from 10. From that we can deduce that this is a combinatorics problem of type n choose k where n = size of the larger set and k = the size of each combination\r
\n" ); document.write( "\n" ); document.write( "n choose k is found by calculating the binomial coefficient found using the formula\r
\n" ); document.write( "\n" ); document.write( "n!/k!(n-k)! thus our answer is 10!/7!(10-7)! = 120 combinations of 7 committee members\r
\n" ); document.write( "\n" ); document.write( "ref: http://en.wikipedia.org/wiki/Combination
\n" ); document.write( "useful link: combinatorics and permutation calculator -http://www.mathsisfun.com/combinatorics/combinations-permutations-calculator.html
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