document.write( "Question 840388: find two consecutive number such that the sum of their squares , reduced by 13, is equal to 100. \n" ); document.write( "

Algebra.Com's Answer #506247 by Fombitz(32388) $\"\"$ $\"About$

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$\"N%5E2%2B%28N%2B1%29%5E2-13=100\"$
\n" ); document.write( " $\"N%5E2%2BN%5E2%2B2N%2B1-13=100\"$
\n" ); document.write( " $\"2N%5E2%2B2N-12=100\"$
\n" ); document.write( " $\"2N%5E2%2B2N-112=0\"$
\n" ); document.write( " $\"N%5E2%2BN-56=0\"$
\n" ); document.write( " $\"%28N-7%29%28N%2B8%29=0\"$
\n" ); document.write( "Two solutions:
\n" ); document.write( " $\"N-7=0\"$
\n" ); document.write( " $\"N=7\"$
\n" ); document.write( "7 and 8.
\n" ); document.write( " $\"N%2B8=0\"$
\n" ); document.write( " $\"N=-8\"$
\n" ); document.write( "-8 and -7. \n" ); document.write( "

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