document.write( "Question 70863: Please help me!!!!: Solution X is 20% alchohol, and solution Y is 80% alchohol. How much of each should be used to make 300 / of a 50% solution.\r
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Algebra.Com's Answer #50623 by ankor@dixie-net.com(22740)\"\" \"About 
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Solution X is 20% alchohol, and solution Y is 80% alchohol. How much of each should be used to make 300 / of a 50% solution.
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\n" ); document.write( "Just by looking at the problem it seems it would be half 20% and half 80%
\n" ); document.write( " since both are 30% away from 50%. However, here is the algebra way
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\n" ); document.write( "We know the two solutions will total 300 units
\n" ); document.write( "x + y = 300
\n" ); document.write( "or
\n" ); document.write( "y = 300 - x
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\n" ); document.write( "Write the per cent equation:
\n" ); document.write( ".20x + .80y = .50(300)
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\n" ); document.write( "Substitute (300-x) for y in the above equation (from the 1st equation)
\n" ); document.write( ".20x + .80(300-x) = .50(300)
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\n" ); document.write( "Multiply what's inside the brackets and you have;
\n" ); document.write( ".20x + 240 - .80x = 150
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\n" ); document.write( ".20x - .80x = 150 - 240
\n" ); document.write( "-.60x = - 90
\n" ); document.write( "x = -90/-.6
\n" ); document.write( "x = + 150 units of 20% stuff, of course 150 units of the 80% also
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\n" ); document.write( "Is this what you had in mind? \n" ); document.write( "
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