document.write( "Question 840469: So, I need help getting walked through the steps of the quadratic equation. If a=1 , b=2.2 x10^-2 and c=-1.2 x10^-4, how does x= 4.5x10^-3?\r
\n" ); document.write( "\n" ); document.write( "I got as far as -2.2x10^2 + or - square root of 9.64x10^-4 and then don't know what to do or if it is right. PLEASE HELP!! I need to get comfortable with the quadratic equation. Thank you!
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Algebra.Com's Answer #506176 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
You have the values for a, b, and c, and you have these from a quadratic equation based on general form \"ax%5E2%2Bbx%2Bc=0\";
\n" ); document.write( "just use the values in the general solution. Simplify and compute! What is the result?\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-2.2%2A10%5E%28-2%29%2B-+%2810%5E%28-2%29%29sqrt%289.64%29%29%2F%282%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x=%28-2.2%2A10%5E%28-2%29%2B-+%2810%5E%28-2%29%293.1048%29%2F%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-2.2%2A10%5E%28-2%29%2B-+3.1048%2A10%5E%28-2%29%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-2.2%2A10%5E%28-2%29%2B-+3.1048%2A10%5E%28-2%29%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"x=%28-5.3%2A10%5E%28-2%29%29%2F2\" OR \"x=%280.90%2A10%5E%28-2%29%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"x=-2.7%2A10%5E%28-2%29\" OR \"x=0.45%2A10%5E%28-2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=-2.7%2A10%5E%28-2%29%29\" OR \"highlight%28x=4.5%2A10%5E%28-3%29%29\"\r
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