document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=840433>Question 840433</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 10 m less then half the length. If the perimeter is 52 meters, find the length of each side of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #506167 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=506167\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 10 m less then half the length. If the perimeter is 52 meters, find the length of each side of the rectangle.<BR>\n" );
document.write( "------<BR>\n" );
document.write( "Let the length be \"L\":<BR>\n" );
document.write( "Then the width = (1/2)L-10<BR>\n" );
document.write( "------<BR>\n" );
document.write( "Perimeter = 2(length + width)<BR>\n" );
document.write( "52 = 2(L + (1/2)L-10)<BR>\n" );
document.write( "26 = (3/2)L - 10<BR>\n" );
document.write( "(3/2)L = 36<BR>\n" );
document.write( "Length = 24 meters<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "Width = (1/2)L-10 = 2 meters<BR>\n" );
document.write( "-------------------------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "------------------------------- </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );