document.write( "Question 840010: The equation, with restriction on x, is the terminal side of an angle theta on standard position.\r
\n" ); document.write( "\n" ); document.write( "-3x+y=0,x is less than or equal to 0\r
\n" ); document.write( "\n" ); document.write( "sin theta=
\n" ); document.write( "cos theta=
\n" ); document.write( "tan theta=
\n" ); document.write( "csc theta=
\n" ); document.write( "sec theta=
\n" ); document.write( "tan theta=
\n" ); document.write( "

Algebra.Com's Answer #506096 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The equation, with restriction on x, is the terminal side of an angle theta on standard position.
\n" ); document.write( "-3x+y=0,x is less than or equal to 0
\n" ); document.write( "Theta is in QII or QIII
\n" ); document.write( "----------------
\n" ); document.write( "y = 3x
\n" ); document.write( "tan(theta) = 3 = y/x
\n" ); document.write( "Since x is negative, y must be negative.
\n" ); document.write( "y = -3 and x = -1
\n" ); document.write( "Therefore r = sqrt(3^2+1^2] = sqrt(10)
\n" ); document.write( "--------------------------------------------
\n" ); document.write( "sin theta= y/r = -3/sqrt(10)
\n" ); document.write( "-----------
\n" ); document.write( "cos theta= = x/r = -1/sqrt(10)
\n" ); document.write( "-------------
\n" ); document.write( "tan theta= y/x = 3
\n" ); document.write( "-----------------
\n" ); document.write( "Note: csc, sec, and tan are the inverse of sin, cos, and tan.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "================
\n" ); document.write( "csc theta=
\n" ); document.write( "sec theta=
\n" ); document.write( "tan theta=
\n" ); document.write( "
\n" ); document.write( "
\n" );