document.write( "Question 840010: The equation, with restriction on x, is the terminal side of an angle theta on standard position.\r
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document.write( "-3x+y=0,x is less than or equal to 0\r
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document.write( "sin theta=
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document.write( "cos theta=
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document.write( "tan theta=
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document.write( "csc theta=
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document.write( "sec theta=
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document.write( "tan theta= \n" );
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Algebra.Com's Answer #506096 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The equation, with restriction on x, is the terminal side of an angle theta on standard position. \n" ); document.write( "-3x+y=0,x is less than or equal to 0 \n" ); document.write( "Theta is in QII or QIII \n" ); document.write( "---------------- \n" ); document.write( "y = 3x \n" ); document.write( "tan(theta) = 3 = y/x \n" ); document.write( "Since x is negative, y must be negative. \n" ); document.write( "y = -3 and x = -1 \n" ); document.write( "Therefore r = sqrt(3^2+1^2] = sqrt(10) \n" ); document.write( "-------------------------------------------- \n" ); document.write( "sin theta= y/r = -3/sqrt(10) \n" ); document.write( "----------- \n" ); document.write( "cos theta= = x/r = -1/sqrt(10) \n" ); document.write( "------------- \n" ); document.write( "tan theta= y/x = 3 \n" ); document.write( "----------------- \n" ); document.write( "Note: csc, sec, and tan are the inverse of sin, cos, and tan. \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================ \n" ); document.write( "csc theta= \n" ); document.write( "sec theta= \n" ); document.write( "tan theta= \n" ); document.write( " \n" ); document.write( " |