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document.write( "The perimeter of a rectangular cement patio is 36 meters. The area is 80 square meters. What are the dimensions of the patio? How do I solve this? \n" );
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Algebra.Com's Answer #506075 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! P=2L+2W \n" ); document.write( "A=LW \n" ); document.write( "P=36 \n" ); document.write( "A=80 \n" ); document.write( "80=LW \n" ); document.write( "L=80/W \n" ); document.write( "36=2(80/W)+2W \n" ); document.write( "36=160/W+2W \n" ); document.write( "36=(160+2W*W)/W \n" ); document.write( "36=(160+2W^2)/W \n" ); document.write( "36W=160+2W^2 \n" ); document.write( "2W^2-36W+160=0 \n" ); document.write( "W^2-18W+80=0 \n" ); document.write( "(W-10)W-8)=0 \n" ); document.write( "W-10=0 \n" ); document.write( "W=10 ANS. \n" ); document.write( "LW=80 \n" ); document.write( "L*10=80 \n" ); document.write( "L=80/10 \n" ); document.write( "L=8 ANS. \n" ); document.write( "IF: \n" ); document.write( "W=8 THEN: \n" ); document.write( "L*8=80 \n" ); document.write( "L=80/8 \n" ); document.write( "L=10 ANS. \n" ); document.write( "PROOF: \n" ); document.write( "2*10+2*8=36 \n" ); document.write( "20+16=36 \n" ); document.write( "36=36 \n" ); document.write( " \n" ); document.write( " |