document.write( "Question 70832This question is from textbook Beginning Algebra
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document.write( ": Factor Completely. 6z^3-27z^2+12z\r
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document.write( "I came up with a completely different answer than the options given and need to verify if this is correct.
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document.write( "my answer is:
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document.write( "3z(z-4)(2z-1)\r
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document.write( "the options for this question is:
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document.write( "a)z(6z-1)(z-12)
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document.write( "b)3z(2z-1)(z-4)
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document.write( "c)z(6z+1)(z+12)
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document.write( "d)z(2z-1)(z-4)\r
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document.write( "Thanks verifying, I appreciate it. \n" );
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Algebra.Com's Answer #50607 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! Your answer is the same as answer b. And it is correct. \n" ); document.write( ". \n" ); document.write( "I suspect that the confusion came because you didn't recognize that they were identical \n" ); document.write( "because the two terms in parentheses appear in reverse order. That doesn't make a bit of \n" ); document.write( "difference in multiplication. No matter what order they are in, if the three terms are there, \n" ); document.write( "the product will be the same. [You could have had the 3z as the last multiplier and it \n" ); document.write( "wouldn't have made your answer different from answer b.] \n" ); document.write( ". \n" ); document.write( "That was a good job of factoring, by the way. \n" ); document.write( " |