document.write( "Question 70832This question is from textbook Beginning Algebra
\n" ); document.write( ": Factor Completely. 6z^3-27z^2+12z\r
\n" ); document.write( "\n" ); document.write( "I came up with a completely different answer than the options given and need to verify if this is correct.
\n" ); document.write( "my answer is:
\n" ); document.write( "3z(z-4)(2z-1)\r
\n" ); document.write( "\n" ); document.write( "the options for this question is:
\n" ); document.write( "a)z(6z-1)(z-12)
\n" ); document.write( "b)3z(2z-1)(z-4)
\n" ); document.write( "c)z(6z+1)(z+12)
\n" ); document.write( "d)z(2z-1)(z-4)\r
\n" ); document.write( "\n" ); document.write( "Thanks verifying, I appreciate it.
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Algebra.Com's Answer #50607 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
Your answer is the same as answer b. And it is correct.
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\n" ); document.write( "I suspect that the confusion came because you didn't recognize that they were identical
\n" ); document.write( "because the two terms in parentheses appear in reverse order. That doesn't make a bit of
\n" ); document.write( "difference in multiplication. No matter what order they are in, if the three terms are there,
\n" ); document.write( "the product will be the same. [You could have had the 3z as the last multiplier and it
\n" ); document.write( "wouldn't have made your answer different from answer b.]
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\n" ); document.write( "That was a good job of factoring, by the way.
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