document.write( "Question 840039: Wilma drove at an average speed of 45 mi/h from her home in City A to visit her sister in City B. She stayed in City B 25 hours, and on the trip back averaged 50 mi/h. She returned home 45 hours after leaving. How many miles is City A from City B? \n" ); document.write( "
Algebra.Com's Answer #506061 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Wilma drove at an average speed of 45 mi/h from her home in City A to visit her sister in City B. \n" ); document.write( " She stayed in City B 25 hours, and on the trip back averaged 50 mi/h. \n" ); document.write( " She returned home 45 hours after leaving.\ \n" ); document.write( " How many miles is City A from City B? \n" ); document.write( ": \n" ); document.write( "From the given information, we know the travel time there and back = 20 hrs \n" ); document.write( ": \n" ); document.write( "let d = the one-way distance \n" ); document.write( "write a time equation; time = dist/speed \n" ); document.write( ": \n" ); document.write( "AB time + BA time = 20 hrs \n" ); document.write( " \n" ); document.write( "Multiply by 450 to clear the denominators \n" ); document.write( "10d + 9d = 9000 \n" ); document.write( "19d = 9000 \n" ); document.write( "d = 9000/19 \n" ); document.write( "d = 473.7 mi is the one-way distance \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check by finding the time each way: \n" ); document.write( "473.7/45 = 10.5 hrs \n" ); document.write( "473.7/50 = 9.5 hrs \n" ); document.write( "-------------------- \n" ); document.write( "total time: 20 hrs \n" ); document.write( " |