document.write( "Question 840039: Wilma drove at an average speed of 45 mi/h from her home in City A to visit her sister in City B. She stayed in City B 25 hours, and on the trip back averaged 50 mi/h. She returned home 45 hours after leaving. How many miles is City A from City B? \n" ); document.write( "
Algebra.Com's Answer #506061 by ankor@dixie-net.com(22740)\"\" \"About 
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Wilma drove at an average speed of 45 mi/h from her home in City A to visit her sister in City B.
\n" ); document.write( " She stayed in City B 25 hours, and on the trip back averaged 50 mi/h.
\n" ); document.write( " She returned home 45 hours after leaving.\
\n" ); document.write( " How many miles is City A from City B?
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\n" ); document.write( "From the given information, we know the travel time there and back = 20 hrs
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\n" ); document.write( "let d = the one-way distance
\n" ); document.write( "write a time equation; time = dist/speed
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\n" ); document.write( "AB time + BA time = 20 hrs
\n" ); document.write( "\"d%2F45\" + \"d%2F50\" = 20
\n" ); document.write( "Multiply by 450 to clear the denominators
\n" ); document.write( "10d + 9d = 9000
\n" ); document.write( "19d = 9000
\n" ); document.write( "d = 9000/19
\n" ); document.write( "d = 473.7 mi is the one-way distance
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\n" ); document.write( "Check by finding the time each way:
\n" ); document.write( "473.7/45 = 10.5 hrs
\n" ); document.write( "473.7/50 = 9.5 hrs
\n" ); document.write( "--------------------
\n" ); document.write( "total time: 20 hrs
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