document.write( "Question 70823This question is from textbook Beginning Algebra
\n" ); document.write( ": Divide x^3 + 2x^2 + x + 12/ x + 3\r
\n" ); document.write( "\n" ); document.write( "I am stuck: I got to this point and need some help....
\n" ); document.write( "x^3 + 2x^2 +x + 12
\n" ); document.write( "x^3 + 3x^2
\n" ); document.write( " _ x^2 +x + 12
\n" ); document.write( " _ x^2 -3x\r
\n" ); document.write( "\n" ); document.write( " 4x + 12\r
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\n" ); document.write( "\n" ); document.write( "This is where I got stuck. Thanks for your help.
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Algebra.Com's Answer #50606 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
I'm not sure why you think you are stuck. You've done everything correctly up to this point.
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\n" ); document.write( "All you have to do now is divide \"4x+%2B+12\" by \"x%2B3\". The answer is \"4\".
\n" ); document.write( ".
\n" ); document.write( "This makes the complete answer to your problem \"x%5E2+-+x+%2B+4\". To check this answer,
\n" ); document.write( "multiply it by \"x%2B3\" and see if you don't get back to the original dividend of \"x%5E3%2B2x%5E2%2Bx%2B12\".
\n" ); document.write( ".
\n" ); document.write( "You seem to understand the division process. Good work!
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