document.write( "Question 840235: log(base 3) of x minus log (base 3) of (x-5)= 1 \n" ); document.write( "
Algebra.Com's Answer #506051 by ewatrrr(24785)\"\" \"About 
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document.write( "Hi,\r
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document.write( "\"log%283%2Cx%29-log+%283%2C%28x-5%29%29+=+1\" ⇒
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document.write( "\"log%283%2C+x%2F%28x-5%29%29+=+log%283%2C3%29\"  Note:  \"1+=+log%283%2C3%29\"
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document.write( "  \"x%2F%28x-5%29+=+3\"
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document.write( "    x = 3(x-5)
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document.write( "    x = 3x - 15
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document.write( "    15 = 2x
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document.write( "   15/2 = x     0r    x =  7 1⁄2  
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