document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1506>Question 1506</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Good evening how would I Solve 2-3(4-x)=x-(3-x) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #506 by </B><A HREF=/tutors/aboutme.mpl?userid=usyim88hk><B>usyim88hk(158)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=usyim88hk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=506\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2-3(4-x) = x-(3-x)<BR>\n" );
document.write( "First multiply 3 and (4-x)<BR>\n" );
document.write( "2-12+3x = x-(3-x)<BR>\n" );
document.write( "Then subtract 12 from 2<BR>\n" );
document.write( "-10+3x = x-(3-x)<BR>\n" );
document.write( "Now, subtract (3-x) from x<BR>\n" );
document.write( "-10+3x = x-3+x<BR>\n" );
document.write( "-10+3x = 2x-3<BR>\n" );
document.write( "Now add three to both sides<BR>\n" );
document.write( "-7+3x = 2x<BR>\n" );
document.write( "subtract 3x from both sides<BR>\n" );
document.write( "-7 = -x<BR>\n" );
document.write( "Divide -1 from both sides<BR>\n" );
document.write( "7 = x </SPAN>\n" );
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