document.write( "Question 840161: find two consecutive even numbers so that 5 times the first exceeds 3 times the second by 54. \n" ); document.write( "
Algebra.Com's Answer #505972 by thejackal(72)\"\" \"About 
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important to remember that if they are consecutive even then the second number will be 2 + the first number.
\n" ); document.write( "So let our two numbers be x and y. y is therefore really x + 2;\r
\n" ); document.write( "\n" ); document.write( "Now we want to choose and x and consequently a y such that x times 5 is exactly 54 larger than 3 times y;\r
\n" ); document.write( "\n" ); document.write( "this can be first expressed like so: 5x > 3y by 54; write this properly it becomes 5x > 3(x + 2) + 54; turn this inequality into an equation by subtracting 54 from both sides to get;\r
\n" ); document.write( "\n" ); document.write( "5x - 54 = 3x + 6\r
\n" ); document.write( "\n" ); document.write( "solve for x\r
\n" ); document.write( "\n" ); document.write( "5x - 3x = 6 + 54 which when simplified becomes 2x = 60 thus x = 30\r
\n" ); document.write( "\n" ); document.write( "now to find y we go back to our original equation for it x + 2 = 30 + 2 = 32\r
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