document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=840120>Question 840120</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of two similar triangles are 15 and 20. If the length of a side of the larger triangle is 4. Find the length of the corresponding side of the smaller triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #505937 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=505937\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of two similar triangles are 15 and 20. If the length of a side of the larger triangle is 4. Find the length of the corresponding side of the smaller triangle.<BR>\n" );
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document.write( "Use a proportion:<BR>\n" );
document.write( "smaller/larger = smaller/larger<BR>\n" );
document.write( "x/4 = 15/20<BR>\n" );
document.write( "x = 4(3/4)<BR>\n" );
document.write( "x = 3<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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