document.write( "Question 840108: The length of a rectangle is 3cm more than twice the width. If the perimeter is 90cm, what are its dimensions? Can you tell me how to write a system for that question? \n" ); document.write( "
Algebra.Com's Answer #505935 by isma95fb(6)![]() ![]() ![]() You can put this solution on YOUR website! First write the data given in a proper format \n" ); document.write( "let L = length, W = width \n" ); document.write( "L - 2W = 3cm \n" ); document.write( "L = 3cm + 2W \n" ); document.write( "but perimeter = 2L + 2W \n" ); document.write( "90cm = 2( 3cm + 2W) + 2W \n" ); document.write( "90cm = 6cm + 5W \n" ); document.write( "W = 16.8cm \n" ); document.write( "and L = 3cm + ( 2 x 16.8) \n" ); document.write( "L = 36.6cm \n" ); document.write( " |