document.write( "Question 840074: crankshaft drives his car certain distance at60 mph, and arrives at his destination one hour earlier than if he had driven at50 mph. how far did he drive \n" ); document.write( "
Algebra.Com's Answer #505923 by isma95fb(6)\"\" \"About 
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From speed= distance/time
\n" ); document.write( "let 60mph=s1 and 50mph=s2
\n" ); document.write( "hence 60mph= distance/t1 and 50mph= distance/t2
\n" ); document.write( "distance= t1 x 60mph ------(i)
\n" ); document.write( "distance= t2 x 50mph ------(ii)
\n" ); document.write( "t1 x 60mph = t2 x 50mph
\n" ); document.write( "but t1 = t2-1
\n" ); document.write( "(t2 - 1) x 60mph = t2 x 50mph
\n" ); document.write( "60mpht2 - 60mph = 50mpht2
\n" ); document.write( "60mpht2-50mpht2 = 60mph
\n" ); document.write( "t2= 6hrs\r
\n" ); document.write( "\n" ); document.write( "from distance = t2 x 50mph
\n" ); document.write( "distance = 300 miles
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