document.write( "Question 840074: crankshaft drives his car certain distance at60 mph, and arrives at his destination one hour earlier than if he had driven at50 mph. how far did he drive \n" ); document.write( "
Algebra.Com's Answer #505923 by isma95fb(6)![]() ![]() ![]() You can put this solution on YOUR website! From speed= distance/time \n" ); document.write( "let 60mph=s1 and 50mph=s2 \n" ); document.write( "hence 60mph= distance/t1 and 50mph= distance/t2 \n" ); document.write( "distance= t1 x 60mph ------(i) \n" ); document.write( "distance= t2 x 50mph ------(ii) \n" ); document.write( "t1 x 60mph = t2 x 50mph \n" ); document.write( "but t1 = t2-1 \n" ); document.write( "(t2 - 1) x 60mph = t2 x 50mph \n" ); document.write( "60mpht2 - 60mph = 50mpht2 \n" ); document.write( "60mpht2-50mpht2 = 60mph \n" ); document.write( "t2= 6hrs\r \n" ); document.write( "\n" ); document.write( "from distance = t2 x 50mph \n" ); document.write( "distance = 300 miles \n" ); document.write( " |