document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=834144>Question 834144</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the measure of two complementary angles are 2x-10 and 4x-2\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #505837 by </B><A HREF=/tutors/aboutme.mpl?userid=LinnW><B>LinnW(1048)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LinnW><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=LinnW><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=505837\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (2x-10) + (4x-2) = 90 , two complementary angles total 90 degrees<BR>\n" );
document.write( "6x -12 = 90<BR>\n" );
document.write( "add 12 to each side<BR>\n" );
document.write( "6x = 102<BR>\n" );
document.write( "x = 17<BR>\n" );
document.write( "The first angle (2x-10) = 2(17) - 10 = 34 -10 = 24<BR>\n" );
document.write( "The second angle (4x-2) = 4(17) - 2 = 68 -2 = 66<BR>\n" );
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