document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=839799>Question 839799</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many ml each of a 15% acetic acid solution and a 30% acetic acid solution must be mixed to obtain 600ml of a 22% acetic acid solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #505831 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=505831\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many ml each of a 15% acetic acid solution and a 30% acetic acid solution must be mixed to obtain 600ml of a 22% acetic acid solution?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "acid + acid = acid<BR>\n" );
document.write( "0.15x + 0.30(600-x) = 0.22*600<BR>\n" );
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document.write( "15x + 30*600 - 30x = 22*600<BR>\n" );
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document.write( "-15x = -8*600<BR>\n" );
document.write( "x = 320 mL (amt. of 15% solution needed)<BR>\n" );
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document.write( "600-x = 280 mL (amt. of 30% solution needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( "</TD></TR></TABLE>\n" );