document.write( "Question 839745: the base of a triangle exceeds the height by 9 centimeters. if the area is 161 square centimeters, find the length of the bas and the height of the triangle. \n" ); document.write( "
Algebra.Com's Answer #505817 by LinnW(1048)\"\" \"About 
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let b = base
\n" ); document.write( " h = height
\n" ); document.write( "b = h + 9
\n" ); document.write( "area = (1/2)(b)(h)
\n" ); document.write( "substituting
\n" ); document.write( "area = (1/2)(h + 9)(h)
\n" ); document.write( "161 = (1/2)(h + 9)(h)
\n" ); document.write( "161 = (1/2)(h^2 + 9h)
\n" ); document.write( "multiply each side by 2
\n" ); document.write( "322 = h^2 + 9h
\n" ); document.write( "add -322 to each side
\n" ); document.write( "0 = h^2 + 9h - 322
\n" ); document.write( "0 = (h+23)(h-14)
\n" ); document.write( "h = -23 or h = 14
\n" ); document.write( "Since we need a positive length we want h = 14
\n" ); document.write( "Since b = h + 9
\n" ); document.write( "b = 14 + 9 = 23
\n" ); document.write( "The base is 23 and height is 14
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