document.write( "Question 70735: Martina leaves home at 9 A.M., bicycling at a rate of
\n" ); document.write( "24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Martina?
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Algebra.Com's Answer #50577 by checkley75(3666)\"\" \"About 
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24T=48(T-2)
\n" ); document.write( "24T=48T-96
\n" ); document.write( "24T-48T=-96
\n" ); document.write( "-24T=-96
\n" ); document.write( "T=-96/-24
\n" ); document.write( "T=4 HOURS JOHN WILL CATCH UP WITH MARTINA
\n" ); document.write( "PROOF
\n" ); document.write( "24*4=48(4-2)
\n" ); document.write( "96=48*2
\n" ); document.write( "96=96
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