document.write( "Question 839637: The area of rectangle lies between 40cm^2 and 45cm^2. If one of the sides is 5 cm, then its diagonal lies between?
\n" ); document.write( "(a) 8cm and 10 cm
\n" ); document.write( "(b)9cm and 11cm
\n" ); document.write( "(c)10cm and 12cm
\n" ); document.write( "(d)11cm and 13cm
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Algebra.Com's Answer #505768 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
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\n" ); document.write( "Note: Area is in cm^2
\n" ); document.write( "The area of rectangle lies between 40cm^2 and 45cm^2. (If one of the sides is 5 cm)
\n" ); document.write( "Using the Pythagorean Theorem
\n" ); document.write( "A = 40cm^2 (8cmx5cm) ⇒ diagonal = \"sqrt%288%5E2+%2B+5%5E2%29+=+sqrt%2889%29+=+9.4\"
\n" ); document.write( "A = 45cm^2 (9cmx5cm) ⇒ diagonal = \"sqrt%289%5E2+%2B+5%5E2%29+=+sqrt%28106%29=+10.3\"
\n" ); document.write( "Wish You the Best in your Studies.
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