document.write( "Question 839475: Given that the quadratic equation x^2-2x-5=0 has 2 different roots, and a second quadratic equation has 2 roots, each of which 2 less than the corresponding root of the given quadratic equation. If the second quadratic equation is x^2+ax+b=0, find the value of a and b. \n" ); document.write( "
Algebra.Com's Answer #505737 by mananth(16946)\"\" \"About 
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Given that the quadratic equation x^2-2x-5=0 has 2 different roots, and a second quadratic equation has 2 roots, each of which 2 less than the corresponding root of the given quadratic equation. If the second quadratic equation is x^2+ax+b=0, find the value of a and b.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-2x-5=0\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-2x%2B1-1-5=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-1%29%5E2-6=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x-1%29%5E2=6\"\r
\n" ); document.write( "\n" ); document.write( "(x-1) = +/- sqrt(6)\r
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\n" ); document.write( "\n" ); document.write( "The roots of the second equation will be \r
\n" ); document.write( "\n" ); document.write( "\"sqrt%286%29-2\", \"-sqrt%286%29-2\"\r
\n" ); document.write( "\n" ); document.write( "sum of roots = -4\r
\n" ); document.write( "\n" ); document.write( "product of the roots = \"sqrt%286%29-2\"*\"-sqrt%286%29-2\"\r
\n" ); document.write( "\n" ); document.write( "=-2\r
\n" ); document.write( "\n" ); document.write( "The general equation is
\n" ); document.write( "x^2-sum of roots(x)+product of the roots=0\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-%28-4%29x%2B%28-2%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B4x-2=0\"\r
\n" ); document.write( "\n" ); document.write( "comparing the equation with\r
\n" ); document.write( "\n" ); document.write( "x^2+ax+b=0\r
\n" ); document.write( "\n" ); document.write( "we get
\n" ); document.write( "a=4, b=-2
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