document.write( "Question 839475: Given that the quadratic equation x^2-2x-5=0 has 2 different roots, and a second quadratic equation has 2 roots, each of which 2 less than the corresponding root of the given quadratic equation. If the second quadratic equation is x^2+ax+b=0, find the value of a and b. \n" ); document.write( "
Algebra.Com's Answer #505737 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Given that the quadratic equation x^2-2x-5=0 has 2 different roots, and a second quadratic equation has 2 roots, each of which 2 less than the corresponding root of the given quadratic equation. If the second quadratic equation is x^2+ax+b=0, find the value of a and b.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x-1) = +/- sqrt(6)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The roots of the second equation will be \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sum of roots = -4\r \n" ); document.write( "\n" ); document.write( "product of the roots = \n" ); document.write( "\n" ); document.write( "=-2\r \n" ); document.write( "\n" ); document.write( "The general equation is \n" ); document.write( "x^2-sum of roots(x)+product of the roots=0\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "comparing the equation with\r \n" ); document.write( "\n" ); document.write( "x^2+ax+b=0\r \n" ); document.write( "\n" ); document.write( "we get \n" ); document.write( "a=4, b=-2 \n" ); document.write( " |