document.write( "Question 839454: A freight train leaves the train station 2 hours before a passenger train. the two trains are traveling in the same direction on parallel tracks. if the rate of the passenger train is 40 mph faster than the freight rain, how fast is each train traveling if the passenger train passes the freight train in 2.5 hours \n" ); document.write( "
Algebra.Com's Answer #505725 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! freight train leaves the train station 2 hours before a passenger train. \n" ); document.write( " the two trains are traveling in the same direction on parallel tracks. \n" ); document.write( " if the rate of the passenger train is 40 mph faster than the freight rain, how fast is each train traveling if the passenger train passes the freight train in 2.5 hours? \n" ); document.write( ": \n" ); document.write( "Let s = the freight train speed \n" ); document.write( "then \n" ); document.write( "(s+40) = Pass train speed \n" ); document.write( ": \n" ); document.write( "When the pass train overtakes the freight, they will have traveled the same dist. \n" ); document.write( "Write a dist equation; dist = time * speed \n" ); document.write( "We know the freight travel time is 2 + 2.5 = 4.5 hrs \n" ); document.write( "4.5s = 2.5(s+40) \n" ); document.write( "4.5s = 2.5s + 100 \n" ); document.write( "4.5s - 2.5s = 100 \n" ); document.write( "2s = 100 \n" ); document.write( "s = 5 mph is the freight \n" ); document.write( "and \n" ); document.write( "50+40 = 90 mph is the pass train \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Confirm this by finding the actual dist each traveled, should be equal. \n" ); document.write( "2.5(90) = 225 mi \n" ); document.write( "4.5(50) = 225 \n" ); document.write( " |