document.write( "Question 70736: There are 850 Douglas fir and ponderosa pine trees in a section of forest bought by Sawz Logging Co. The company paid an average of $300 for each Douglas fir and $225 for each ponderosa pine. If the company paid $217,500 for the trees, how many of each kind did the company buy? \n" ); document.write( "
Algebra.Com's Answer #50572 by checkley75(3666)\"\" \"About 
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850=D+P D=850-P NOW SUBSTITUTE (850-P) FOR D IN THE SECOND EQUATION
\n" ); document.write( "217,500=300D+225P
\n" ); document.write( "217,500=300(850-P)+225P
\n" ); document.write( "217,500=255,000-300P+225P
\n" ); document.write( "300P-225P=255,000-217,500
\n" ); document.write( "75P=37,500
\n" ); document.write( "P=37,500/75
\n" ); document.write( "P=500 NUMBER OF PONDEROSA PINES
\n" ); document.write( "850-500=350 NUMBER OF DOUGLAS FIRS
\n" ); document.write( "PROOF
\n" ); document.write( "217,500=300*350+225*500
\n" ); document.write( "217,500=105,000+112,500
\n" ); document.write( "217,500=217,500
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