document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=839476>Question 839476</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if f(-3)=-120, for f(x)=x^4+x^3-19x^2+kx+30.. find f(1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #505719 by </B><A HREF=/tutors/aboutme.mpl?userid=josh_jordan><B>josh_jordan(263)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josh_jordan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josh_jordan><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=505719\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To find f(1), we need to first find k in our function.  We do this by replacing each of our x's with -3 and setting that equal to -120:\r<BR>\n" );
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document.write( "(-3)^4 + (-3)^3 - 19(-3)^2 + k(-3) + 30 = -120 ----->\r<BR>\n" );
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document.write( "81 + (-27) - 19(9) - 3k + 30 = -120 ----->\r<BR>\n" );
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document.write( "81 - 27 - 171 - 3k + 30 = -120 ----->\r<BR>\n" );
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document.write( "-3k - 87 = -120\r<BR>\n" );
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document.write( "Next, we will add 87 to both sides of our equation, which will give us:\r<BR>\n" );
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document.write( "-3k = -33\r<BR>\n" );
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document.write( "Dividing both sides of our equation by -3 will give us the value of k:\r<BR>\n" );
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document.write( "k = 11\r<BR>\n" );
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document.write( "Now, we can replace k with 11 in our function and replace all of the x's with 1:\r<BR>\n" );
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document.write( "(1)^4 + (1)^3 - 19(1)^2 + (11)(1) + 30 ----->\r<BR>\n" );
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document.write( "1 + 1 - 19 + 11 + 30 ----->\r<BR>\n" );
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document.write( "24\r<BR>\n" );
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document.write( "Therefore, our answer is 24 </SPAN>\n" );
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