document.write( "Question 839291: An investment club invest part of $8000 at 10% annual interest and the rest at 12%. If the annual income from these investment is $900, how much was invested at each rate. \n" ); document.write( "

Algebra.Com's Answer #505646 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "Let x and y represent amount saved at 10% and 12% respectively
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document.write( "    x  + y = $8,000    0r  
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document.write( " .10x + .12y = $900
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document.write( " .10(8,000 - y) + .12y = 900  |solving the system of EQs by substitution
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document.write( "             .02y = 900 - 800
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document.write( "              .02y = 100
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document.write( "                 y = $5000  and x = $3000
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document.write( "CHECKING our answer***
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document.write( " = $900
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document.write( "Wish You the Best in your Studies
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