document.write( "Question 839227: The sum of the first 4 terms of an arithmetic sequence is 24. The 7th term exceeds the 4th term by 24. Determine the sum of the first 12 terms \n" ); document.write( "
Algebra.Com's Answer #505628 by alicealc(293)\"\" \"About 
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The formula for the nth term in an arithmetic sequence is:
\n" ); document.write( "Un = U1 + (n - 1)d
\n" ); document.write( "in which Un is the nth term, U1 is the 1st term, and d is the difference.
\n" ); document.write( "So, for the 2nd term: U2 = U1 + (2 - 1)d = U1 + d
\n" ); document.write( "for the 3rd term: U3 = U1 + (3 - 1)d = U1 + 2d
\n" ); document.write( "for the 4th term: U4 = U1 + (4 - 1)d = U1 + 3d
\n" ); document.write( "and so on.\r
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\n" ); document.write( "\n" ); document.write( "The sum of the first 4 terms of an arithmetic sequence is 24:
\n" ); document.write( "U1 + U2 + U3 + U4 = 24
\n" ); document.write( "U1 + (U1 + d) + (U1 + 2d) + (U1 + 3d) = 24
\n" ); document.write( "4U1 + 6d = 24
\n" ); document.write( "divide all by 2:
\n" ); document.write( "2U1 + 3d = 12\r
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\n" ); document.write( "\n" ); document.write( "The 7th term exceeds the 4th term by 24:
\n" ); document.write( "7th term: U7 = U1 + (7 - 1)d = U1 + 6d
\n" ); document.write( "U7 = U4 + 24
\n" ); document.write( "U1 + 6d = U1 + 3d + 24
\n" ); document.write( "U1 + 6d - U1 - 3d = 24
\n" ); document.write( "6d = 3d + 24
\n" ); document.write( "6d - 3d = 24
\n" ); document.write( "3d = 24
\n" ); document.write( "d = 24/3 = 8\r
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\n" ); document.write( "\n" ); document.write( "2U1 + 3d = 12
\n" ); document.write( "2U1 + 3(8) = 12
\n" ); document.write( "2U1 + 24 = 12
\n" ); document.write( "2U1 = -12
\n" ); document.write( "U1 = 12/2 = -6\r
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\n" ); document.write( "\n" ); document.write( "The sum of the first n term can be found by using this formula:
\n" ); document.write( "Sn = n/2 * {2U1 + (n - 1)d}\r
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\n" ); document.write( "\n" ); document.write( "so, the sum of the first 12 term is:
\n" ); document.write( "S12 = 12/2 * {2(-6) + (12 - 1)8}
\n" ); document.write( "S12 = 6 * (-12 + 11*8)
\n" ); document.write( "S12 = 6 * (-12 + 88)
\n" ); document.write( "S12 = 6 * 76
\n" ); document.write( "S12 = 456
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