document.write( "Question 70780: Harold is twiCE AS OLD as jack,who is three years older than dan.if harolds age is five times dan age ,how old in years id jack \n" ); document.write( "

Algebra.Com's Answer #50560 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let h=Harold, j=jack, and d=dan. If Harold is twice as old as jack then you could write this relationship as
\n" ); document.write( " $\"2j=h\"$ For instance if jack is 10, then harold is 20
\n" ); document.write( "And if jack is 3 years older than dan then it can be written as
\n" ); document.write( " $\"d%2B3=j\"$
\n" ); document.write( "And if harold's age is 5 times dan's age then
\n" ); document.write( " $\"5d=h\"$
\n" ); document.write( "First set the 2 h equations equal to each other
\n" ); document.write( " $\"2j=5d\"$ Solve for d
\n" ); document.write( " $\"d=%282%2F5%29j\"$
\n" ); document.write( "Then plug this equation of d into d of the equation d+3=j
\n" ); document.write( " $\"d%2B3=j\"$
\n" ); document.write( " $\"%282%2F5%29j%2B3=j\"$ Plug in $\"d=%282%2F5%29j\"$
\n" ); document.write( " $\"3=j-%282%2F5%29j\"$ Subtract (2/5)j from both sides
\n" ); document.write( " $\"3=%283%2F5%29j\"$ subtract fractions
\n" ); document.write( " $\"3%2A%285%2F3%29=j\"$ solve for j
\n" ); document.write( " $\"j=5\"$
\n" ); document.write( "So jack is 5 years old, harold is 10, and dan is 2 \n" ); document.write( "

\n" );