document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=70783>Question 70783</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factor by grouping:\r<BR>\n" );
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document.write( "3b^2+16b+5\r<BR>\n" );
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document.write( "I am having a very hard time with this. Is there any trick or hints you can provide?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50559 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50559\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Factor by grouping:\r<BR>\n" );
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document.write( "3b^2+16b+5<BR>\n" );
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document.write( "Think of two numbers whose product is 3*5=15<BR>\n" );
document.write( "and whose sum is 16<BR>\n" );
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document.write( "The numbers are 1 and 15<BR>\n" );
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document.write( "Replace 16b in the problem with b+15b to get:<BR>\n" );
document.write( "3b^2+b+15b+5<BR>\n" );
document.write( "Factor the 1st two terms and the last two terms separately:<BR>\n" );
document.write( "b(3b+1) + 5(3b+1)<BR>\n" );
document.write( "Factor out the common factor of (3b+1) to get:<BR>\n" );
document.write( "(3b+1)(b+5<BR>\n" );
document.write( "Those are the factors you want.<BR>\n" );
document.write( "This method is called the AC method because you wanted to find<BR>\n" );
document.write( "two numbers whose product was AC=3*5=15.<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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