document.write( "Question 839129: Applying the 68- 95- 99.7 Rule. When designing the placement of a CD player in a new model car, engineers must consider the forward grip reach of the driver. Women have forward grip reaches that are normally distributed with a mean of 27.0 inches and a standard deviation of 1.3 inches (based on anthropometric survey data from Gordon, Churchill et al.). Use the 68- 95- 99.7 rule to find the indicated quantity.
\n" ); document.write( "a. Find the percentage of women with forward grip reaches between 24.4 inches and 29.6 inches.
\n" ); document.write( "b. Find the percentage of women with forward grip reaches less than 30.9 inches.
\n" ); document.write( "c. Find the percentage of women with forward grip reaches between 27.0 inches and 28.3 inches.
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Algebra.Com's Answer #505584 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "27.0 inches and a standard deviation of 1.3 inches
\n" ); document.write( "Usimg the 68- 95- 99.7\r
\n" ); document.write( "\n" ); document.write( "a. Find the percentage of women with forward grip reaches between 24.4 inches and 29.6 inches. 95%
\n" ); document.write( " b. Find the percentage of women with forward grip reaches less than 30.9 inches.\"50+%2B+99.7%2F2\" = 99.85%
\n" ); document.write( " c. Find the percentage of women with forward grip reaches between 27.0 inches and 28.3 inches. \"68%2F2\" = 34%\r
\n" ); document.write( "\n" ); document.write( "For the normal distribution:
\n" ); document.write( "one standard deviation from the mean accounts for about 68.2% of the set
\n" ); document.write( "two standard deviations from the mean account for about 95.4%
\n" ); document.write( "and three standard deviations from the mean account for about 99.7%.
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