document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=70761>Question 70761</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395862981/algebrahomeworkh>Algebra 2 Explorations and Applications</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I must solve the following equation, and then round the answer to the nearest hundreth, while using the Log way. 1+8(0.43)^2u=3 <BR>\n" );
document.write( "I placed Log in front of both equations like 2uLog(0.43)=Log(3/9). However I keep getting a completely different answer than what the book has provided, which is .82. Please solve this solution, thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50558 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50558\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1+8(0.43)^2u=3<BR>\n" );
document.write( "Subtract 1 from both sides to get:<BR>\n" );
document.write( "8(0.43)^2u=2<BR>\n" );
document.write( "log[8(0.43)^2u] =log2<BR>\n" );
document.write( "log 8 + log(0.43)^2u =log 2<BR>\n" );
document.write( "2u[log0.43] = log 2 - log8<BR>\n" );
document.write( "2u[log0.43] = log(1/4)<BR>\n" );
document.write( "2u = log(1/4)/log(0.43)<BR>\n" );
document.write( "2u = 1.64258<BR>\n" );
document.write( "u=0.82<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );