document.write( "Question 838986: A radiator contains 8 liters of a 25% antifreeze solution. How much should be drained and replaced with pure antifreeze to produce a 45% antifreeze solution? (Round your answer to two decimal places.) \n" ); document.write( "
Algebra.Com's Answer #505471 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
v = amount of liters to drain and replace\r
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\n" ); document.write( "\n" ); document.write( "\"%288%2A25-25v%2B100v%29\" represents the amount of antifreeze material resulting in the radiator. A factorization will be useful: \"200%2B%28100-25%29v\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28200%2B%28100-25%29v%29%2F8=45\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28%28200%2B75v%29%2F8=45%29\"
\n" ); document.write( "Solve for v.
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\n" ); document.write( "\"200%2B75v=360\"
\n" ); document.write( "\"75v=160\"
\n" ); document.write( "\"v=2.133333\"... liters to remove and replace
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\n" ); document.write( "About 2 liters 130 mililiters
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