document.write( "Question 838995: HELP!!!! 4 times the third, of three consecutive integers, is 51 less than 3 times the sum of the first and second integers.\r
\n" ); document.write( "\n" ); document.write( "Find the third integer? \n" ); document.write( "

Algebra.Com's Answer #505466 by josmiceli(19441) $\"\"$ $\"About$

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Let the integers be $\"+n+\"$ , $\"+n%2B1+\"$ , and $\"+n+%2B+2+\"$
\n" ); document.write( " $\"+4%2A%28+n%2B2+%29+=+3%2A%28+n+%2B+n+%2B+1+%29+-+51+\"$
\n" ); document.write( " $\"+4n+%2B+8+=+3%2A%28+2n+%2B+1+%29+-+51+\"$
\n" ); document.write( " $\"+4n+=+6n+%2B+3+-+51+-+8+\"$
\n" ); document.write( " $\"+4n+=+6n+-+56+\"$
\n" ); document.write( " $\"+6n+-+4n+=+56+\"$
\n" ); document.write( " $\"+2n+=+56+\"$
\n" ); document.write( " $\"+n+=+28+\"$
\n" ); document.write( " $\"+n+%2B+1+=+29+\"$
\n" ); document.write( " $\"+n+%2B+2+=+30+\"$
\n" ); document.write( "The 3rd integer is 30
\n" ); document.write( "check:
\n" ); document.write( " $\"+4%2A%28+n%2B2+%29+=+3%2A%28+n+%2B+n+%2B+1+%29+-+51+\"$
\n" ); document.write( " $\"+4%2A%28+30+%29+=+3%2A%28+28+%2B+29+%29+-+51+\"$
\n" ); document.write( " $\"+120+=+3%2A57+-+51+\"$
\n" ); document.write( " $\"+120+=+171+-+51+\"$
\n" ); document.write( " $\"+120+=+120+\"$
\n" ); document.write( "OK \n" ); document.write( "

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