document.write( "Question 838995: HELP!!!! 4 times the third, of three consecutive integers, is 51 less than 3 times the sum of the first and second integers.\r
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Algebra.Com's Answer #505464 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "three consecutive integers: , , 
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document.write( "Question states***
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document.write( "4 times the third is 51 less than 3 times the sum of the first and second integers.
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document.write( " ***4(x+2) = 3[x + (x+1)] -51   | Solving for x
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document.write( "    4x + 8 = 3(2x+1) - 51
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document.write( "    4x + 8 = 6x + 3 - 51
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document.write( "      56 = 2x
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document.write( "      28 = x , the first Integer.  The third integer is 
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document.write( "CHECKING our answer***
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document.write( "    120 = 120
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document.write( "Wish You the Best in your Studies.
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