document.write( "Question 838142: step 1: 30/π∫ max: 2 min: 0) (π/6)*sec((πx)/6)dx = 30/π(ln|sec((xπ)/6)+tan((xπi)/6)|] (max: 2 min: 0) \r
\n" ); document.write( "\n" ); document.write( "step 2: = 30/π(ln|sec((π)/__?__)+tan((π)/__?__)| - ln|1+0|] \r
\n" ); document.write( "\n" ); document.write( "step 3: = (30/π)ln(__?__+sqrt(__?__)) \r
\n" ); document.write( "\n" ); document.write( "step 4: = __?__ (rounded to three decimal places) \r
\n" ); document.write( "\n" ); document.write( "step 5: Thus the area of the bounded region is approximately __?__ (rounded to three decimal places). \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Can you please tell me what to put where it reads __?__
\n" ); document.write( "

Algebra.Com's Answer #505421 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
Apparently you are integrating the function
\n" ); document.write( "\"+5sec%28pi%2Ax%2F6%29=%2830%2Fpi%29%28pi%2F6%29%2Asec%28pi%2Ax%2F6%29\"
\n" ); document.write( "to find the area under the curve between \"x=0\" and \"x=2\" .
\n" ); document.write( "step 1: \"%2830%2Fpi%29int%28%28pi%2F6%29%2Asec%28pi%2Ax%2F6%29%2Cdx%2C0%2C2%29=%2830%2Fpi%29\"\"abs%28+%22ln%22abs%28sec%28pi%2Ax%2F6%29%2Btan%28pi%2Ax%2F6%29%29%29\"\"matrix%283%2C1%2C2%2C%22+%22%2C0%29\"
\n" ); document.write( "The antiderivative or indefinite integral of the function
\n" ); document.write( "\"%28pi%2F6%29%2Asec%28pi%2Ax%2F6%29\" is the function
\n" ); document.write( "\"f%28x%29=%22ln%22abs%28sec%28pi%2Ax%2F6%29%2Btan%28pi%2Ax%2F6%29%29\"
\n" ); document.write( "The definite integral between the limits \"x=0\" and \"x=2\" is calculated as
\n" ); document.write( "\"f%282%29-f%280%29\" .
\n" ); document.write( "For \"x=2\" , \"pi%2Ax%2F6=pi%2A2%2F6=pi%2Fred%283%29\" so \"f%282%29=%22ln%22abs%28sec%28pi%2Fred%283%29%29%2Btan%28pi%2Fred%283%29%29%29\"
\n" ); document.write( "For \"x=0\" , \"pi%2Ax%2F6=pi%2A0%2F6=0\" so \"f%280%29=%22ln%22abs%28sec%280%29%2Btan%280%29%29=%22ln%22abs%281%2B0%29\"
\n" ); document.write( "step 2: =\"%2830%2Fpi%29\"
\n" ); document.write( "\"sec%28pi%2F3%29=1%2Fcos%28pi%2F3%29=1%2F%280.5%29=highlight%282%29+\" , \"tan%28pi%2F3%29=highlight%28sqrt%283%29%29+\" , and \"%22ln%22abs%281%2B0%29%29=ln%281%29=0\" , so (rounded to three decimal places).
\n" ); document.write( "step 3: =\"%2830%2Fpi%29%2Aln%28highlight%282%29%2Bhighlight%28sqrt%283%29%29+%29\"
\n" ); document.write( "My calculator says that
\n" ); document.write( "step 4: =\"highlight%2812.576%29\"
\n" ); document.write( "
\n" );