document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=838742>Question 838742</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A triangle lakefront lot has a perimeter of 600 feet. One side is 50 feet shorter than 2 times the shortest side, while the third side is 150 feet longer than the shortest side.<BR>\n" );
document.write( "Find the lengths of all three sides? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #505354 by </B><A HREF=/tutors/aboutme.mpl?userid=LinnW><B>LinnW(1048)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LinnW><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=LinnW><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=505354\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let s = short side<BR>\n" );
document.write( " m = medium side<BR>\n" );
document.write( " l = long side<BR>\n" );
document.write( "m = 2s - 50<BR>\n" );
document.write( "l = 150 + s<BR>\n" );
document.write( "perimeter = s + m + l<BR>\n" );
document.write( "600 = s + m + l<BR>\n" );
document.write( "substitute (2s - 50) for m, and (150 + s) for l<BR>\n" );
document.write( "600 = s + (2s - 50) + (150 + s)<BR>\n" );
document.write( "600 = 4s + 100<BR>\n" );
document.write( "add -100 to each side<BR>\n" );
document.write( "500 = 4s<BR>\n" );
document.write( "divide each side by 4<BR>\n" );
document.write( "125 = s<BR>\n" );
document.write( "m = 2(125) - 50 = 250 - 50 = 200<BR>\n" );
document.write( "l = 150 + s = 150 + 125 = 275<BR>\n" );
document.write( "So the side lengths are 125,200 and 275 .<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );