document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=838751>Question 838751</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve the linear system using method of substition.\r<BR>\n" );
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document.write( "3m-6n=1<BR>\n" );
document.write( "m+3n=2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #505349 by </B><A HREF=/tutors/aboutme.mpl?userid=mxgirl22><B>mxgirl22(39)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mxgirl22><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mxgirl22><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=505349\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve the linear system using method of substitution.\r<BR>\n" );
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document.write( "1.) 3m-6n=1<BR>\n" );
document.write( "2.) m+3n=2\r<BR>\n" );
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document.write( "***NOTE: I numbered each equation so I can refer back to them easier.\r<BR>\n" );
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document.write( "Step 1.) Look at each equation to see which one would be easier to manipulate. It looks like it will be the 2nd one.\r<BR>\n" );
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document.write( "1.) 3m-6n=1<BR>\n" );
document.write( "2.) m+3n=2\r<BR>\n" );
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document.write( "Step 2.) Get \"m\" by itself.\r<BR>\n" );
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document.write( "2.) m+3n=2\r<BR>\n" );
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document.write( "m+3n-3n=2-3n\r<BR>\n" );
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document.write( "m=2-3n\r<BR>\n" );
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document.write( "Step 3.) Now that we have \"m\" by itself in equation 2, we can plug in m=2-3n for the \"m\" in equation 1.\r<BR>\n" );
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document.write( "1.) 3m-6n=1\r<BR>\n" );
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document.write( "3(2-3n)-6n=1<BR>\n" );
document.write( "6-9n-6n=1<BR>\n" );
document.write( "6-15n=1<BR>\n" );
document.write( "6-6-15n=1-6<BR>\n" );
document.write( "-15n=-5<BR>\n" );
document.write( "-15n/-15=-5/-15<BR>\n" );
document.write( "n=0.333333(repeating) or n=1/3\r<BR>\n" );
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document.write( "Step 4.) Plug in the value we got for \"n\" (n=1/3) into equation 2.\r<BR>\n" );
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document.write( "2.) m+3n=2\r<BR>\n" );
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document.write( "m+3(1/3)=2<BR>\n" );
document.write( "m+1=2<BR>\n" );
document.write( "m+1-1=2-1<BR>\n" );
document.write( "m=1\r<BR>\n" );
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document.write( "Step 5.) Check with original equation(s) 1&2 using the value m=1 and n=1/3.\r<BR>\n" );
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document.write( "1.) 3m-6n=1\r<BR>\n" );
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document.write( "3(1)-6(1/3)=1<BR>\n" );
document.write( "3-6(1/3)=1<BR>\n" );
document.write( "3-2=1<BR>\n" );
document.write( "1=1   <----- Checks with equation 1.\r<BR>\n" );
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document.write( "2.) m+3n=2\r<BR>\n" );
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document.write( "1+3(1/3)=2<BR>\n" );
document.write( "1+1=2<BR>\n" );
document.write( "2=2   <----- Checks with equation 2.\r<BR>\n" );
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document.write( "Step 6.) Answer.\r<BR>\n" );
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document.write( "m=1 and n=1/3\r<BR>\n" );
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