document.write( "Question 838771: Car A travels 120 miles in the same time that car B travels 150 miles. If car B travels 10 mph faster than car A, how fast is each car travelling? \n" ); document.write( "
Algebra.Com's Answer #505320 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r
\n" ); document.write( "Let r=car A's rate
\n" ); document.write( "Then r+10=car B's rate\r
\n" ); document.write( "\n" ); document.write( "Time travelled by car A=120/r
\n" ); document.write( "Time travelled by car B=150/(r+10)
\n" ); document.write( "Now we are told that these times are the same, soooo:
\n" ); document.write( "120/r=150/(r+10) multiply each side by r(r+10)
\n" ); document.write( "120(r+10)=150r simplify
\n" ); document.write( "120r+1200=150rsubtract 120r from each side
\n" ); document.write( "120r-120r+1200=150r-120r
\n" ); document.write( "30r=1200
\n" ); document.write( "r=40mph---Car A speed
\n" ); document.write( "r+10=40+10=50 mph -----Car B's speed (or rate)
\n" ); document.write( "CK
\n" ); document.write( "120/40=150/50
\n" ); document.write( "3=3\r
\n" ); document.write( "\n" ); document.write( "Hope this helps--ptaylor
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