document.write( "Question 838771: Car A travels 120 miles in the same time that car B travels 150 miles. If car B travels 10 mph faster than car A, how fast is each car travelling? \n" ); document.write( "
Algebra.Com's Answer #505320 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r \n" ); document.write( "Let r=car A's rate \n" ); document.write( "Then r+10=car B's rate\r \n" ); document.write( "\n" ); document.write( "Time travelled by car A=120/r \n" ); document.write( "Time travelled by car B=150/(r+10) \n" ); document.write( "Now we are told that these times are the same, soooo: \n" ); document.write( "120/r=150/(r+10) multiply each side by r(r+10) \n" ); document.write( "120(r+10)=150r simplify \n" ); document.write( "120r+1200=150rsubtract 120r from each side \n" ); document.write( "120r-120r+1200=150r-120r \n" ); document.write( "30r=1200 \n" ); document.write( "r=40mph---Car A speed \n" ); document.write( "r+10=40+10=50 mph -----Car B's speed (or rate) \n" ); document.write( "CK \n" ); document.write( "120/40=150/50 \n" ); document.write( "3=3\r \n" ); document.write( "\n" ); document.write( "Hope this helps--ptaylor \n" ); document.write( " |