document.write( "Question 838722: In a collection of coins there are 7 less dimes than there are quarters. if the value of the collection is $3.85, then how many dimes are there? \n" ); document.write( "
Algebra.Com's Answer #505306 by LinnW(1048)![]() ![]() You can put this solution on YOUR website! d = number of dimes \n" ); document.write( "q = number of quarters \n" ); document.write( "d = q - 7 \n" ); document.write( "0.10d + 0.25q = 3.85 \n" ); document.write( "substitute (q - 7) for d \n" ); document.write( "0.10(q - 7) + 0.25q = 3.85 \n" ); document.write( "0.10q - 0.70 + 0.25q = 3.85 \n" ); document.write( "0.35q - 0.70 = 3.85 \n" ); document.write( "add 0.70 to each side \n" ); document.write( "0.35q = 4.55 \n" ); document.write( "divide each side by 0.35 \n" ); document.write( "q = 4.55/0.35 \n" ); document.write( "q = 13 \n" ); document.write( "d = 13-7 = 6 \n" ); document.write( "$0.60 in dimes + $3.25 in quarters is $3.85 \n" ); document.write( " |