document.write( "Question 838722: In a collection of coins there are 7 less dimes than there are quarters. if the value of the collection is $3.85, then how many dimes are there? \n" ); document.write( "
Algebra.Com's Answer #505306 by LinnW(1048)\"\" \"About 
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d = number of dimes
\n" ); document.write( "q = number of quarters
\n" ); document.write( "d = q - 7
\n" ); document.write( "0.10d + 0.25q = 3.85
\n" ); document.write( "substitute (q - 7) for d
\n" ); document.write( "0.10(q - 7) + 0.25q = 3.85
\n" ); document.write( "0.10q - 0.70 + 0.25q = 3.85
\n" ); document.write( "0.35q - 0.70 = 3.85
\n" ); document.write( "add 0.70 to each side
\n" ); document.write( "0.35q = 4.55
\n" ); document.write( "divide each side by 0.35
\n" ); document.write( "q = 4.55/0.35
\n" ); document.write( "q = 13
\n" ); document.write( "d = 13-7 = 6
\n" ); document.write( "$0.60 in dimes + $3.25 in quarters is $3.85
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