document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=838757>Question 838757</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with this problem, I don't even know where to begin:<BR>\n" );
document.write( "A chemist has three different acid solutions. The first acid solution contains 30% acid, the second contains 40%, and the third contains 60%. He wants to use all three solutions to obtain a mixture of 161 liters containing 50% acid, using twice as much of the 60% solution as the 40% solution. How many liters of each solution should be used?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #505303 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=505303\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> c=2b,<BR>\n" );
document.write( "a+b+c=161,<BR>\n" );
document.write( ".3a+.4b+.6c=.5*161<BR>\n" );
document.write( "a=23.,   b=46.,   c=92. </SPAN>\n" );
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