document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=70769>Question 70769</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm lost with this question. Can you help?\r<BR>\n" );
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document.write( "One side of a triangle is 2/3rds as long as the second side and the second side is 2/3rds as long as the third side. The perimeter = 95cm. What is the length of the longest side?\r<BR>\n" );
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document.write( "Would the equation be:\r<BR>\n" );
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document.write( "95 = X + (X x 2/3) + (X x 2/3)2/3\r<BR>\n" );
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document.write( "Is X the longest side and how do I find X?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50527 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50527\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> S1=2/3*S2<BR>\n" );
document.write( "S2=2/3*S3<BR>\n" );
document.write( "S1+S2+S3=95<BR>\n" );
document.write( "2/3*S2+2/3*S3+S3=95<BR>\n" );
document.write( "2/3(2/3*S3)+2/3*S3+S3=95<BR>\n" );
document.write( "4/9*S3+2/3*S3+S3=95<BR>\n" );
document.write( "(4*S3)/9+(2*S3)/3+S3=95<BR>\n" );
document.write( "(4*S3+2*3*S3+9*S3)/9=95<BR>\n" );
document.write( "(4S3+6S3+9S3)/9=95 ADD THE LEFT HAND TERMS & CROSS MULTIPLY<BR>\n" );
document.write( "19S3=855<BR>\n" );
document.write( "S3=855/19<BR>\n" );
document.write( "S3=45 RDS. FOR THE THIRD (LONGEST) SIDE.\r<BR>\n" );
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