document.write( "Question 838454: What is equation for sequence 1, 1, 1/2, 1/3, 1/4, 1/9... \n" ); document.write( "
Algebra.Com's Answer #505231 by Edwin McCravy(20056)\"\" \"About 
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document.write( "1/1, 1/1, 1/2, 1/3, 1/4, 1/9...\r\n" );
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document.write( "Sequence of denominators bn: 1,1,2,3,4,9,...\r\n" );
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document.write( "5(b3)-6(b1) = 5(2)-6(1) = 10-6 = 4 = b5\r\n" );
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document.write( "5(b4)-6(b2) = 5(3)-6(1) = 15-6 = 9 = b6\r\n" );
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document.write( "So a recursion equation for the sequence of denominators is:\r\n" );
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document.write( "b1=1,b2=1,b3=2,bn=5bn-2-6bn-4\r\n" );
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document.write( "Therefore a recursion equation for the given sequence an is\r\n" );
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document.write( "a1=1,a2=1,a3=1/2,an=5/an-2-6/an-4    \r\n" );
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document.write( "Edwin

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