document.write( "Question 838693: a rectangle has a diagonal length of 15 ft and a width that is 3 more than its length. find the lendth, width and perineter of the rectangle \n" ); document.write( "
Algebra.Com's Answer #505227 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there,\r \n" ); document.write( "\n" ); document.write( "Diagonal = 15 ft \n" ); document.write( "Length = x ft \n" ); document.write( "Width = x + 3 ft \n" ); document.write( "Using Pythagoras theorem. \n" ); document.write( "x^2 + (x + 3)^2 = 25^2 \n" ); document.write( "x^2 + x^2 + 6x + 9 = 225 \n" ); document.write( "2x^2 + 6x - 216 = 0 \n" ); document.write( "Divide throughout by 2 \n" ); document.write( "2(x^2 + 3x - 108 = 0) \n" ); document.write( "2(x - 9)(x + 12) = 0 \n" ); document.write( "x = 9 or x = - 12. \n" ); document.write( "As we cannot use a negative value \n" ); document.write( "x = 9 \n" ); document.write( "and x + 3 = 12 \n" ); document.write( "x^2 + (x + 3)^2 = 25^2 \n" ); document.write( "9^2 + 12^2 = 25^2 \n" ); document.write( "81 + 144 = 225. \n" ); document.write( "Hope this helps.:-) \n" ); document.write( " \n" ); document.write( " |