document.write( "Question 838693: a rectangle has a diagonal length of 15 ft and a width that is 3 more than its length. find the lendth, width and perineter of the rectangle \n" ); document.write( "
Algebra.Com's Answer #505227 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
Hi there,\r
\n" ); document.write( "\n" ); document.write( "Diagonal = 15 ft
\n" ); document.write( "Length = x ft
\n" ); document.write( "Width = x + 3 ft
\n" ); document.write( "Using Pythagoras theorem.
\n" ); document.write( "x^2 + (x + 3)^2 = 25^2
\n" ); document.write( "x^2 + x^2 + 6x + 9 = 225
\n" ); document.write( "2x^2 + 6x - 216 = 0
\n" ); document.write( "Divide throughout by 2
\n" ); document.write( "2(x^2 + 3x - 108 = 0)
\n" ); document.write( "2(x - 9)(x + 12) = 0
\n" ); document.write( "x = 9 or x = - 12.
\n" ); document.write( "As we cannot use a negative value
\n" ); document.write( "x = 9
\n" ); document.write( "and x + 3 = 12
\n" ); document.write( "x^2 + (x + 3)^2 = 25^2
\n" ); document.write( "9^2 + 12^2 = 25^2
\n" ); document.write( "81 + 144 = 225.
\n" ); document.write( "Hope this helps.:-)
\n" ); document.write( "
\n" ); document.write( "
\n" );