document.write( "Question 70648: please help\r
\n" ); document.write( "\n" ); document.write( "4/5x + 2 greater or equal to 2/5\r
\n" ); document.write( "\n" ); document.write( "and\r
\n" ); document.write( "\n" ); document.write( "1-6x less than or equal to 7
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Algebra.Com's Answer #50521 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
please help\r
\n" ); document.write( "\n" ); document.write( "4/5x + 2 greater or equal to 2/5
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\n" ); document.write( "Write it:
\n" ); document.write( "(4/5)x + 2 >= 2/5
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\n" ); document.write( "Get rid of those annoying denominators, multiply equation by 5 and you have:
\n" ); document.write( "4x + 10 >= 2
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\n" ); document.write( "Subtract 10 from both sides:
\n" ); document.write( "4x >= 2 -10
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\n" ); document.write( "4x >= -8
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\n" ); document.write( "Divide both sides by 4
\n" ); document.write( "x >= -8/4
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\n" ); document.write( "x >= -2
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\n" ); document.write( "1-6x less than or equal to 7
\n" ); document.write( "1 - 6x <= 7
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\n" ); document.write( "Subtract 1 from both sides and you have:
\n" ); document.write( "-6x <= 7 - 1
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\n" ); document.write( "-6x <= 6
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\n" ); document.write( "We must have the variable (x) to be positive, so we multiply equation by -1
\n" ); document.write( "When we do this, we must reverse the inequality sign from < to >
\n" ); document.write( "+6x >= -6
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\n" ); document.write( "Divide both sides by 6
\n" ); document.write( "x >= -6/6
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\n" ); document.write( "x >= -1
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\n" ); document.write( "What about this? Did this make sense to you now?\r
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