document.write( "Question 838663: Hi there,\r
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document.write( "I am trying to work out the following: 52 card deck without replacement. 4 players 1 card each. First player has a heart. Each of the other 3 players get a card. What are the chances of ANY of the other 3 cards being a heart (or how do you work it out).
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document.write( "This was where I got to: Second player: probability is 12/51 (twelve hearts left with 51 cards), Third player 12/50, Fourth 12/49. How do I determine the probability of ANY of the other players having a HEART?
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document.write( "What do I do with these numbers - 0.2352941176470588, .24,
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document.write( "0.2448979591836735 ?
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document.write( "If I wanted to find out what was the probability of them ALL being HEARTS I would multiply these numbers (I think)\r
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document.write( "Would you recommend any text book / accessible material on this type of probability question?\r
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document.write( "Thanking you in advance\r
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document.write( "Kyran \n" );
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Algebra.Com's Answer #505187 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! 52 cards, 13 Hearts, 39 Non-Hearts \n" ); document.write( "First player - Heart \n" ); document.write( "51 cards, 12 Hearts, 39 Non-Hearts \n" ); document.write( "Look at the possible draws of the next three cards (H - heart, N - non-heart) and calculate the probabilities of each, they are all independent events. \n" ); document.write( "NNN- \n" ); document.write( "NNH- \n" ); document.write( "NHN- \n" ); document.write( "NHH- \n" ); document.write( "HNN- \n" ); document.write( "HNH- \n" ); document.write( "HHN- \n" ); document.write( "HHH- \n" ); document.write( "If you sum up all of the probabilities, they do add up to 1. They must, these are the only possible draws. \n" ); document.write( "Now look for the ones that have at least 1 heart. \n" ); document.write( "Or look for the one that has no hearts and subtract from 1. \n" ); document.write( "P(at least 1 heart)= \n" ); document.write( "Yes, all of them being hearts would be HHH, |