document.write( "Question 838604: A triangle has a Base length of x + 4 and a perpendicular height of x + 3, it's area is 10cm^2.
\n" ); document.write( "Find x
\n" ); document.write( "Find the Base and Height of the Triangle\r
\n" ); document.write( "\n" ); document.write( "I've tried a variety of methods and no matter what the Area ends up being 15cm^2, so obviously my height and Base Length are wrong.
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Algebra.Com's Answer #505158 by lwsshak3(11628)\"\" \"About 
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A triangle has a Base length of x + 4 and a perpendicular height of x + 3, it's area is 10cm^2.
\n" ); document.write( "Find x
\n" ); document.write( "Find the Base and Height of the Triangle
\n" ); document.write( "***
\n" ); document.write( "Area of a triangle=1/2*base*height
\n" ); document.write( "(1/2)(x+4)(x+3)=10
\n" ); document.write( "(x+4)(x+3)=20
\n" ); document.write( "x^2+7x+12=20
\n" ); document.write( "x^2+7x-8=0
\n" ); document.write( "(x+8)(x-1)=0
\n" ); document.write( "x=-8(reject)
\n" ); document.write( "or
\n" ); document.write( "x=1
\n" ); document.write( "Base=x+4=5cm
\n" ); document.write( "Height=x+3=4cm
\n" ); document.write( "
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