document.write( "Question 838544: when chris drives his car to work it takes 1/2 hour. when he takes the bus it takes 3/4 hour. the average rate of the bus is 12 mph less than his rate when driving. find the ditance he travels to work. \n" ); document.write( "
Algebra.Com's Answer #505138 by josgarithmetic(39617)\"\" \"About 
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Assign variables to whatever you not know.
\n" ); document.write( "Use RT=D and fill in a data table.\r
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\n" ); document.write( "\n" ); document.write( "__________________speed___________time_________distance
\n" ); document.write( "CAR_________________r_____________1/2__________r(1/2)
\n" ); document.write( "BUS_______________(r-12)__________3/4_________(r-12)(3/4)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The car and the bus method use the same distance to reach the same destination, \"highlight_green%28r%281%2F2%29=%28r-12%29%283%2F4%29%29\".
\n" ); document.write( "Solve for the rate first, and then you can compute the distance. Start the equation solving by multiplying both sides by 4:\r
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\n" ); document.write( "\n" ); document.write( "\"2r=%28r-12%29%2A3\"
\n" ); document.write( "\"2r=3r-36\"
\n" ); document.write( "\"highlight%2836=r%29\"
\n" ); document.write( "-
\n" ); document.write( "Since the distance is \"r%281%2F2%29\", this is \"highlight%2836%281%2F2%29=highlight%2818%29%29\" miles
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