document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=838374>Question 838374</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 60% alcohol solution is to be mixed with a 42% alcohol solution.  How many liters of the 60% solution should be used to make 30 liters of a 54% alcohol solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #505043 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=505043\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A 60% alcohol solution is to be mixed with a 42% alcohol solution. How many liters of the 60% solution should be used to make 30 liters of a 54% alcohol solution?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "alch + alch = alch<BR>\n" );
document.write( "0.60x + 0.42(30-x) = 0.54*30<BR>\n" );
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document.write( "60x + 42*20 - 42x = 54*30<BR>\n" );
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document.write( "18x = 12*30<BR>\n" );
document.write( "x = 20 liters (amt. of 60% solution needed)<BR>\n" );
document.write( "30-x = 10 liters (amt. of 42% solution needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( "</TD></TR></TABLE>\n" );